DrChinese's latest activity

1. If you are drawing a distinction between photons as Bohmian particles versus electrons as Bohmian particles, we are veering away from...

Haha, I guess there is plenty of room to disagree on the meaning of words like "contextual". :smile: You have stated BM is contextual...

Exactly. And note that in Norsen's paper, he explicitly states that one particle of an entangled pair will always be measured before...

How is this not the same as Superdeterminism? Of course the precursor conditions are not typical in your description because the Pilot...

As with many things, precise definitions of things like “contextuality” make the difference. The reason I agree with Demystifier on...

The two references I provided in the previous reply are non-relativistic QM. Literally, there is nothing whatsoever about relativistic...

Photons that never coexisted (A measured before B created): https://arxiv.org/abs/1209.4191 Photons entangled after they (both A and B)...

Norsen provides a nice summary which fits my example nicely: "One of the particles will encounter its measuring device first; the...

And I am saying that logically, after Alice's measurement, nothing in the universe has any net effect on the evolution of B's...

That's not quite true. In quantum optics, for example, it's quite common to treat photons in an essentially non-relativistic way. See...

"Photon" is a limited term. That's why I said "quantum EM field" instead when I referred to the treatment in Ballentine. Only a very...

@Demystifier per your Norsen reference on Spin in BM, post #9: "In the top frame, particle 1 (on the right) encounters its SGz device...

I could not see immediately how one makes things work if "measurement on particle A" does not leave a lasting effect on the overall wave...

Ok, so wouldn't the statement then be that Bohmian mechanics just makes the non-locality obvious? I do have an issue with the view...

Sure, let's agree the measurement on A leaves a lasting effect on the guidance equation going forward. I would assume that it would...