Recent content by DreamWarrior

Ahhh...well, that is easier than my method. Better yet, it produces the same answer. With the easier problem (2 questions), I opted to compute using the inverse (1 - the probability that you get everything wrong). Obviously, for a 2 question problem that is the only way you can get less...

Let me prefix by stating that this is not really a homework problem, just something I am curious about. I posted it here because it is probably too easy to go into the "big boy" forums :smile:. Last night my wife said she needed a 23% on her final to maintain a grade of A in her course. I...