Recent content by Drew552

Ok, thank you for all your help, I think I've got it down now. ill post again if i come to any complications. Thanks a lot :)

so is the coefficient of friction constant over one horizontal surface no matter the mass?

so it would be 40=u+9.8 Assuming 40 is the mass

gravity?

The force is the 2 entities rubbing together?

so if i had a 20N force pushing a against a box the normal force would equal 20N right?

a entity pushing against something thus making the kinetic energy?

F(kinetic)= u(coefficient) x F(normal)??

I do? Well point taken then, thanks for the hint, ill try to to do my best at getting the answer but still unsure how to get the friction coefficient

.

Am i allowed to attach a picture of the chart and also the picture of the simulator??

Yes it is being pushed on an horizontal surface. And yes the only horizontal forces are the force and friction. No i am not given the acceleration but I am assuming it could possibly be 9.81 and it doesn't give me the coefficient of friction.

Well its on a friction simulator online. I'm pushing on a unknown mass with 500N of applied force. The friction force comes out as 125N and the sum of the forces is 375N to the right direction. I am asked to find the mass and the weight of the object. I want to know the mass of the object which...

Its a fill in the chart question so its not really a word for word one, i have all the values but this one. If i can provide anything else please tell me.