Recent content by duhfluteplaye

I got .45 kgm/s for change in momentum. I got (after just using the initial velocity instead of both components) 45N for the force. I got 30.72 m for the height of the apogee. For acceleration i used 9.81 since it is free fall. I got 5 s for time (2.5 up to the apogee and the same amount back...

well for change in momentum i did .015*30sin 55 and then .015*30cos55 and got both components. For the force i did change in momentum/time so .015*30sin55 and then divided by .01. For the apogee i did vf^2=vi^2+2adeltax so 30sin55 squared+2(9.81) and then solved for delta x. for the total x...

Projectile Motion Question! HELP! Homework Statement There is a marble (15g) in a spring shooter that is shot at 30 m\s at 55 degrees. The ball is on the spring shooter for .01s. Homework Equations What is the change in momentum right as it is shot? What is the force? What is the...

Projectile motion and mechanical energy and a bunch of other stuff...help