Recent content by dylbester

mean of X is defined as ∫ x * f (x) dx over the domain of definition of X ∫ x (x + 1) / 8 dx = ∫ (x^2 + x) / 8 dx = x^3 / 24 + x^2 / 16 + c Over the interval [-1, 3], we get: (3^3 - (-1)^3) / 24 + (3^2 - (-1)^2) / 16 = 7/6 + 1/2 = 5/3 Im I right?

Thank you for your time, I really appreciate it I have no idea where to even begin

A continuous random variable x has the following probability function: f(X)=(X+1)/8 -1<=X<=3 0 Otherwise 1. Find the Pr(X<=2) 2. Find the mean of X

$p(x) ={p}^{x}*{(1-p)}^{1-x}$ for $x=0.1$ $0$ otherwise Where $p$ is such that $0<=p<=1$ Question: Find the mean and variance of $X