Recent content by eadanlin

OK. I think I know the answer (probably) If it is a plane wave, then yes, ∇⋅E = 0. One can simply write E as a plane wave and see if it is 0. In fact, there is actually no charge or current whatsoever. If it is not a plane wave, and one finds ∇⋅E ≠ 0, then σ - iωɛ = 0 has to be true. As some...

Hey, thank you guys for your time and thoughts. There are some interesting thought; I need some time to sink in. anyway, thanks!

Thank you for your replies. Sorry for the confusion. So this is a plane wave in a homogeneous medium characterized by finite conductivity σ and permittivity ɛ. Therefore, σ and ɛ are not a function of space; just think of them as constants (hence, ∇⋅ɛE = ɛ∇⋅E, ∇⋅σE = σ∇⋅E). I followed the...

Hi, this looks stupid and simple, but I just can't get my head around it. Assuming a homogeneous medium. The electromagnetic continuity equation goes as ∇⋅J + ∂ρ/∂t = 0 since J = σE, ρ = ɛ∇⋅E, and assuming the time dependence exp(-iωt) we have σ∇⋅E - iωɛ∇⋅E = 0 (σ - iωɛ)∇⋅E = 0 So, σ - iωɛ = 0...