Recent content by EB3 Effects

Copy that. The end result is the same though, yes?

This is making sense to me. I don't understand the mathmatic symbols in some of the prior posts, so it becomes difficult to learn the formula on my way to a solution. Sorry boys, but I'm a 52 year old left brained visual thinker. I appreciate your contributions. Everett

I don't know where to start on calculating the volume of the steel Russ. The surface area x thickness? I would have to make estimates for multiple layers and such. The volume of the sand will be determined by how much weight is necessary to achieve negative buoyancy for the project and yes, I...

Lets do it! density of fluid is 1000 kilograms/meter3 volume is 317.7 cubic meters force of gravity is 9.18 Newtons/kilogram The equation is Fb=VxDxFg so 317.7 x 1000 x 9.18 = 2,916,486 pounds to keep the car under water?

Hello all and thanks in advance for your contributions. I am calculating how much weight it will take to keep a car on the floor of a 5' deep pool. The engine and transmission have been removed as well as the hood and trunk. The remaining body weighs 2,000 lb. The cab will be sealed air...

Hello all, My name is Everett, I am a special effects coordinator and found this site while searching for information on negative bouyancy equations in order to keep an airtight car underwater.