Recent content by Ebies

Thank you very much for the speedy reply Sir, you are a star and your help and guidance are greatly appreciated!

Thanks gneill yet gain for the response, I comprehend the mesh current concept now, what I do not understand however is: you know between the individual terms for a single equation: how do you decide if it's a "+" or "-" term? I watched a lecture last night which said it is always "+" for...

when using mesh analysis to determine the voltage drop direction, do you use conventional current flow or do you use the clockwise current you chosen at the beginning when assigned your clockwise mesh currents...? I am asking so I know when to add or subtract when doing the "KVL" walk... I am a...

I3(-Z3) - V2 - Z5(I3-I2) = 0...Eq 3 new and revised eq 3

thnx gneill

can you please confirm if I have conducted my kvl loops correctly as per diagram on post #9 V1 - I1Z1 - Z4(I1-I2) = 0...Eq 1 -V3 - Z5(I2-I3) - Z4(I2-I1) = 0...Eq 2 I3Z3 - V2 - Z5(I3-I2) = 0...Eq 3

thanks gneill, you are a star

this just seems too simple, thus casting doubt in my mind... I have IL1=V1/j4 and IL2=V2/j6 and hat would be the two current generators IL1 and IL2 respectively

in fact I will calculate what I think it is and post it here for confirmation

so use ohms law with the voltage source and its series impedance to find i for each respective loop independently and i will be my current source respectively?

for this particular problem it has an extension as part 1c which states the following: (c) by transforming the two voltage sources and their associated reactances into current sources (and thus form a pair of Norton generators)... Now am I correct in saying the way I answered 1B I kind of...

ok problem solved... made a mistake in my addition on the two currents... thanks for the assistance gneill... yet again very reliable and helpful... enjoy xmas eve and stay safe... :0)

magnitudes were fine but the phase angle is what's waaaay out. I used cos trig function in both thevenins and superposition theorem so can't really understand why the difference... let me quickly add the two currents again just to eliminate any possible error I could have made...

well should they not equal the current previously calculated in part a) of the original question when added together? (the current calculated when I done the thevenins part)

yes I can supply the figures... this is what I worked out and from both IL1+IL2 you can see it does not match up with the Thevenins figure...