Recent content by eddieb340

Thanks Doc Al and everyone for their help, I actually didnt get the measurements of how deep we submerged the Aluminum block and your right that it would be some a minute change it really doesn't matter. I wish i had taken the measurement it would be nice to see how little the volume changes...

With all do respect, the volumes are actually different. Think about it. Water is 1000 times more dense than air. So the outside force of the water is crushing the block, therefore making the volume smaller. What happens when you put a balloon 10,000 feet under water? It will be smaller...

No, its a lab problem and he won't let us calculate it directly. We have to use buoyant forces. So we weighed the mass in the air and then in the water, found the different and solved for the volume from this following equation: T + B = mg where B = pgV but you can't weigh the mass in...

How do you find the exact buoyant force of air? B = pgV where p = density of air (1.29kg/m3) g = 9.81 m/s2 V = volume displaced The problem is, you can't measure Volume directly. You have to do it experimentally by weighing a mass in air and then in water. I can...

I understand that the true mass of the block never changes but we can't directly measure the true mass due to the buoyancy force of air. T + Bwater = mg In the above equation the mg was recorded by weighing the block in air. The T was recorded by weighing the block in water and the B was the...

I've got an interesting question about a Buoyancy problem we were given in Lab today. We were given an unknown block and we were asked to find its density without directly measuring its volume. So we found the mass in air and in water. Mass in air was 267.65g Mass in water was 237.76g...