Recent content by Edidas
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Circular Motion/Energy: Find the position of the rings when tension = 0
I looked at when Θ = 0° and determined that N = 3mg so in that case would it be N + 3mgcosΘ = Fc?- Edidas
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- Forum: Introductory Physics Homework Help
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Circular Motion/Energy: Find the position of the rings when tension = 0
Here's my first attempt at a solution: First, I calculated the speed of one ring at the point where the tension would be zero. 3mgr(1-cosΘ ) = (1/2) * (3m) * (v^2). 3m * v^2 = 6mgr(1-cosΘ) Next, since I wanted the centripetal force, I took the result I got and divided by the radius. Fc =...- Edidas
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- Circular Position Rings Tension
- Replies: 5
- Forum: Introductory Physics Homework Help