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Since ac = v2 and r is constant, ac changes according with v. v is represented by n rpm. n rpm => ac,Earth/0.378 gMercury Wanted: k, where k is constant such that k * n => ac = 4 gMercury: k * n => 4/(ac,Earth/0.378) Since k * n rpm is the velocity and a is altered according with v: k =...

acentrifugal = v2/r The direction of acentrifugal is straight outwards from the edge of the circular motion.

Edit: gMercury = 0.378 * gEarth Question: How many rpm(in terms of n) should it make to produce 4 gMercury at its outer end?

Supposed answer = 0.482n