Recent content by emilyb1995

Just clicked. Thank you so much. Got it right. :)

Because the masses are suspended, would F2+F3=F1? P.S. Sorry for all the questions, I'm having some trouble wrapping my head around it.

Hmmm. You lost me. Would the system's Net Force equation just be m1g-T3+T2-T1-m2g+T1-m3g

Would T1 be acting on it as well?

That makes sense. So, with the 3k force, would it be F2=T2-(m2g+m3g) ? And if so, how would I solve for T1?

Okay. So, if the 3kg mass is m2 and the 2kg mass is m3: F2=T2-m2g and F3=T1-m3g Are those correct? Everything plugged in would be: F1=6a=58.8-T3 F2=3a=T2-29.4 F3=2a=T1-19.6

It would just be Fg and Ft acting on each mass, correct?

A pulley is massless and frictionless. The masses 2 kg, 3 kg, and 6 kg are suspended as in the figure. (Figure Attached) What is the tension T1 in the string be- tween the two blocks on the left-hand side of the pulley? The acceleration of gravity is 9.8 m/s2 . Answer in units of N...