Point taken...It was reinforced in class. But from this question, the rate in and rate out i get are:
$$rate IN = concentration*flow
= (200kg/400,000L)*(500L/hr)
= 0.25kg/hr$$
$$rate OUT = conc*flow
= (x/400,000L)(500L/hr)
= x/800 kg/hr$$
Which sets up the diff eqn,:
$$dx/dt = 0.25 -...