Recent content by es4

Ok, that means I suppose to find "f (friction)" <<<<< which is, f (friction) = mu * N (weight m*g)... thanks.

Do you mean, just the rate of deceleration? which was >>> a = - 0.25 or -0.3 m/s^2

What the question mean by "constant frictional resistance" in terms of formula? I suppose they meant... "resistance force (f)" which is, >> f = m * a. So, here is my try... m = 1.15 ton or 1150 kg vi = 20 m/s vf = 0 d = 800 m v^2 - u^2 = 2ad 0 - 20^2 = 2a* 800 - 400 = 2a* 800 - 400 /...

hmm, seems like I got to brush up some old memories. Appreciated the response though.

I guess you are trying to trigger log out of me. That means, other things are correct though... :)

Hi, here is my attempt... Feel free to correct me if I am doing it wrong. v1 = .8 m3 p1 = 250 or 250000 n/m2 p2 = 7000 or 7000000 n/m2 Cp = 1010 Cv = 7321. isothermally p1v1 = p2v2 [Boyle equality law (isothermal process)] 250 000 * .8 = 7000000 * v2 7000000 * v2 = 250 000 * .8...

Learning about mechanical physics. Feel free to knock me. I reply when I am free... (& appreciate the same)

Just figuring out things.