so I get -250000/150 ln (abs(7.5-150y/250,000) +c = t
So solve for y ? One of my friends did this in maple and I'm just not getting an equation for y that agrees with him :(
Okay, so...
dy/(7.5-150y/250000) = dt
I understand that concept, but I have zero idea how to evaluate the resulting integral, on the left hand side anyways.
Okay I understand what I've done so far, but for some reason I'm having a lot of trouble solving it...I understand to do with my initial value after I solve...but what are my first few algebra moves?
Okay, so I know ds/dt = salt in - salt out.
As for Salt In:
I know I have 50gal/hr x .15lb / gal = 7.5 lb / hour
For Salt Out:
I have 150 gal/hr x the concentration at that given time.
Do I represent that as 150 x (25,000lb + 7.5 t)/250,000
where 25,000 is the starting amount of salt...
Homework Statement
The problem can be found here: http://alex.fangsoft.net/math.pdf
I have completed Task #2, it is Task #1 that I am very lost on. Our teacher has really thrown us head first into the water with this one, I am very unfamiliar with differential equations and their...