Recent content by fifthrapiers

Ah yes! That was quite helpful. How does this look: [x,\hat{H}]\psi = [x,\frac{p^2}{2m}]\psi = [x,p\cdot\frac{p}{2m}]\psi = [x,p]\frac{p}{2m}\psi + p[x,\frac{p}{2m}]\psi = i\hbar\frac{p}{2m}\psi + p[x,p\cdot\frac{1}{2m}]\psi = i\hbar\frac{p}{2m}\psi + p[x,p]\frac{1}{2m}\psi +...

The orig question was [x,h] for # 1, I just forgot to put in the brackets... Yes, that's the whole point, I'm not sure how. I showed my work.

I'm having trouble with commutators. I have to solve them 2 ways. First, using [x,p]=i\hbar and other identities/formulas, and the the second method the "direct way". 1.) x,\hat{H} My work: [x,\hat{H}]\psi &= x\hat{H}\psi - \hat{H}x\psi = x \left ( \frac{p^2}{2m} + V(x) \right )\psi -...