Recent content by first21st

Re: A probability question ok. Got it! Thanks a lot.James

Re: Basic Algebra Question: Need to be solved! Thanks a lot. That was a quite complicated one!

Re: A probability question Thank you very much man! But I am still wondering why did we MULTIPLY # the number of ways to choose 1 girl from 10 # AND # 2 boys from 15 #, instead of ADDING these two operands?

Re: Basic Algebra Question: Need to be solved! That means, 210*3=630 will be spent on shirts, and rest of the 180 will be spent on ties. Am I right?Thanks, James

Re: A probability question Thanks for your reply. It's really a great way of learning. I highly appreciate your approach. Is the solution something like: (15 C 2) * (10 C 1)/ (25 C 3)If it is correct, could you please explain why did we divide it with the number of ways of choosing 3 students...

Re: Basic Algebra Question: Need to be solved! Thanks for your reply. Yes, the problem is we have just one equation for two unknowns. But another point here is that, if X is amount spent for shirts, and Y is the amount spent for ties, Y=810-X. Now, we need to find out the maximum value of X...

In a class, there are 15 boys and 10 girls. Three students are selected at random. The probability that 1 girl and 2 boys are selected, is: A. 21/46 B. 25/117 C. 1/50 D. 3/25 Could you please solve this problem with proper explanation? Thanks, James

Re: Basic Algebra Question: Need to be solved! Yes, it's 70*S + 30*T = 810. But the amounts spent on shirt and ties separately are unknown. The other parameter which might be helpful here is that, with this amount of 810, a maximum number of shirts have been purchased and rest have been spent...

The Price of each shirt is 70 dollars and the price of each tie is 30 dollars. He spent a total amount of exactly 810 dollars and bought the maximum number of shirts. What is the ratio of the number of Shirt to Ties? Help Please!Thanks, James