Recent content by flash123

thanks hallsofevy that was helpful! since x and y could be anything so the possible eigen vectors corresponding to eigen value 0 are [1 0 0],[0 1 0] or [1 1 0] please tell me am i correct now?

hey the problem is e^(1/(n*logn)) log n is with n log n is not in numerator

hey anyone please can tell me this one: A=lim(e^(1/n*logn)) (n tends to 0) i took log on both sides and then by using l hospital rule i arrive at lim(-1/n) (n tends to 0) can't solve further...please help

use sin^-1 (y)=xy and then differentiate both sides

sorry hallsofevy, the correct answer is [a 0 0] but after solving the eqn [A-lamdaI][X]=0 or AX=lamdaX i got az+0+0 = 0 so how to proceed further and arrive at the correct answer?

hey sourabh, i did try to solve the question. i got eigen values as 0, 0 , 0 and after using [A-lambdaI]X=0 i am getting 0X1+0X2+aX3=0 which makes eigen vector as [0 0 0 ] whereas the answer is [0 0 a]

any1 can please tell me the eigen vector for following matrix: [0 0 a 0 0 0 0 0 0] please elaborate ur answer!