Recent content by Flop880

Yea I saw the expressions for Xc but I have a hard time solving for it since I don't have R and other variables that I need

Homework Statement problem is attachedHomework Equations formula sheet is attachedThe Attempt at a Solution 1. I=v/z=110v/11Ω=10A 2. sinø=(Imax)(X)/v=(10A)(9Ω)/110V ø=54.9° 3. I don't know what to do for this. I want to use Xc=1/ωC and solve for C but I need to first find Xc somehow

I just got the right answer by multiplying by the width, not length. so dA= dx w, since dx is the length that's changing times the width which gives area. What do you mean by double integral? Doesn't that give volume?

Homework Statement Problem is attached Homework Equations A formula sheet is also attached The Attempt at a Solution flux=\intB dA from .31m to .82 B=u I(enclosed)/2(pi)(d) d=x dA=dx L so ∫ (u)(I)(L)dx / 2(pi)(x) from .31m to .82m remember x=d in the pic. My answer is 3.9687e-7 and its...