Thank you very much for your response. Except now I'm confused for a new reason.
So if a one kilo object is one meter away from the Earth then it will have
-(6.67300 × 10-11 × 5.9742 × 1024 × 1)/(12) = -3.98658366 × 1014 potential energy? So it will have a huge amount of negative...
I read that lifting an object higher increases its potential energy. Is this true? I can't see how, considering:
Ep = mgh
F = mg
so Ep = Fh
F = (G x m1 x m2)/ d2
so
Ep = (G x m1 x m2 x d)/ d2
so
Ep = (G x m1 x m2)/ d
So the greater the distance between the object and the...