Hi
I have problems understanding the Kelvin equation:
\ln {p_v \over p_0}= {2 \sigma V_m \over rR_mT}
You can rewrite Kelvin equation in the folowing form as well:
p_v =p_0*exp({2 \sigma\over r}*{M \over \rho_lR_mT})
It is obvious from the above equations that p_v is always bigger...