Recent content by fulton33

  1. fulton33

    Calculating the equations for the tangent/normal lines

    That makes sense about 10. That would make it x=-1?
  2. fulton33

    Calculating the equations for the tangent/normal lines

    10. Does that mean for number 10 the equation would be x=0 because at x=-1 f'(-1)=0? 12. Does that mean that for number 12 y=0 would then be correct?
  3. fulton33

    Calculating the equations for the tangent/normal lines

    9. When I do this problem I know my slope is -3 because f'(2)=-3. I then went and substituted and got y+5=-3(x-2) which simplified to y=-3x+1 10. I get lost here because the tangent slope would be 0, which would give me the equation y=-2. The normal means perpendicular and the perpendicular...