Recent content by Funken

Actually, after repeating the evaluation of the integral on those manifolds more cautiously I found that for S^2 the integral is exactly the identity operator, while for \mathbb{H}^2 the factor 1/2 remains. For \mathbb{R}^{2n} the situation changes too as c=2^{-n}. So no universal result...

Just as the title says, suppose X is a symmetric manifold and \hat{S}(x) is the linear operator associated to \sigma_x\in G for some unitary irreducible representation, where \sigma_x is the group element that performs reflections around x (remember X=G/H for H\subset G). Now take the...