Recent content by genius

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    Solving for Cn to get wave function

    I need to solve Cn for a wave function, and have reached the following integral: Cn = -[√(1/a)](a/nπ)[cos(nπx/a)(ψ1(x)+ψ2(x))+∫cos(u)(dψ1(x)/dx)dx+∫cos(u)(dψ2(x)/dx)dx]This is a simplified version of the original equation, for elaboration Cn is the constant for linear combinations of a wave...
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    How did they get 1=A^2(L/4) when integrating?

    I realized that just as I sent that reply, thanks for making me analyze my mistake. I used u substitution and got the correct answer.
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    How did they get 1=A^2(L/4) when integrating?

    I agree that cos^2 (x) must be different than the situation we are facing. My mistake then would be foolishly treating 2πx/L as the x in cos^2(x), which upon thought would be incorrect because you are integrating it with dx. If you look at it closely you can see how I replaced x from the...
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    How did they get 1=A^2(L/4) when integrating?

    My question's purpose was for someone to explain how exactly the solution was A^2=4/L? If someone could explain how the problem was integrated to get the following result, I can analyze it and derive what I am missing.
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    How did they get 1=A^2(L/4) when integrating?

    I also wrote my steps while preforming the problem, and did so at least three times. I caught a mistake once, but that didn't get me the correct answer.
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    How did they get 1=A^2(L/4) when integrating?

    The part I skipped was showing how I integrated, which is because of the way I learned to integrate cos^2. The following website sums up what I did, http://calc101.com/special_2.html. I basically used this rule to integrate, which is how I got the part you are asking about.
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    How did they get 1=A^2(L/4) when integrating?

    I merely integrated cos^2(2πx/L), can you elaborate upon what I am missing? If you are correct, then maybe this missing factor could be what I am lacking!
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    How did they get 1=A^2(L/4) when integrating?

    TSny, I wasn't familiar on how to put in the dimensions for the right hand side with this text editor. The dimensions can be seen in the pdf, but sorry for not being able to include it.
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    How did they get 1=A^2(L/4) when integrating?

    I was looking for questions to practice normalizing a wave function, so I visited the following online pdf, http://people.physics.tamu.edu/syeager/teaching/222/hw1solution.pdf. The first question was to find the normalization constant, A of ψ(x) = A cos (2πx/L) for (−L/4) ≤ x ≤ (L/4). After...
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