Recent content by gomdul2

Thanks Redbelly 98 :) change in the volume of mercury = delta V = V-Vo = (vol.coeficient)(Vo)(delta T) = V - (1.287 X 10^-4) = (1.83 X 10^-4)(1.287X10^-4)(100-12deg) 2.072 X 10^-6 = V - (1.287 X 10^-4) Therefore, V = 1.30772 X 10^-4 m^3. Since V = (pi)(r^2)(h) and r is fixed...

Homework Statement A glass tube of radius 0.80cm contains liquid mercury to a depth of 64.0cm at 12deg. Find the depth of the mercury column at 100 deg. Assume that the linear expansion coefficient of the glass is 10 X 10^-6 K-1 and the linear expansion coefficient of mercury is 0.61 X 10^-4...