Recent content by googooloo

Thanks a lot then it is solved :smile:

well i need to find at and ar... i have constant accelerate about 0.5 m/s2 and the time which it required from me about 15 sec. SO> 0.5=delta V/ delta t=delta v/15 so delta v is 7.5...v0 is 0 m/s so V is 7.5... r=30 m ar=V2/r=1.875... at is 0.5 m/s2... so √(al2 + ar2) will be...

Oh, then how can i solve this question?

Yes that is exactly what you said, and sorry for the language :biggrin: anyways how can i find √(al2 + ar2)?

Is this correct? by the area under the F vs time => integrate of F.dt= delta p and intagrate of F.dt = delta U = - W = -delta K. so Delta P = -Delta K => mv(f) - mv(i) = [(1/2)*m*v(i)^2] - [(1/2)*m*v(f)^2] =>m(vf-vi)= (1/2)m[v(i)^2 - v(f)^2] =>2Vf-2Vi=vi^2-vf^2 => by vi=34...

Well, it represents delta P...but as u know delta P = p(2) - p (1) i have the mass, and same as v(1) but i don't have v (2)...so i can't find F(max) because of the lack of v(2)...

Need it Fast please! Homework Statement The question is: A ball with 58 Grams of mass strikes against a wall. The initial speed is 35 m/s. The path of the strike is always vertical to the wall (90 degrees of angle between them). figure 1 represents F(force) diagram. What is the maximum...

physic for today please help me! Homework Statement A car starts moving from a stay position. The path of its movement has a circular form. The radius of the circle that the car is moving on, is constantly 0.5 (m/s^2). a) what is the pure linear acceleration of the car after 15 seconds...