Recent content by GWR309
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MHB Lagrange Multipliers: Find Extrema of f(x,y)=x^2y
Yeah I tried. I ended up with 2y^2+sqrt(2)y-6 which doesn't seem right and if it is right, I don't know how to solve it -
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MHB Lagrange Multipliers: Find Extrema of f(x,y)=x^2y
f(x,y)=x^2y with the constraint of x^2+2y^2=6 Use lagrange multipliers to find the extrema. Thanks! -
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MHB GWR309's question at Yahoo Answers regarding Lagrange multipliers
for general lagrange multipliers problems, how do I determine if it is a max, min or neither? -
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MHB GWR309's question at Yahoo Answers regarding Lagrange multipliers
Where did you get the system though? this: y=λ x=−2λ