Recent content by GZM

Would the answer be left in variables or would there be an exact numerical answer? and when you say I'll get 2 equations with 2 unknowns you mean each or 2 unknowns overall, because I get 2 unknowns each and when I equate them to each other i get 2 unknowns in a single expression

Haha thanks I really appreciate the help, new to the forum but I love it so much already, you guys here really help guide me through without actually giving me the answer just what I needed XD

Homework Statement Problem states : A student walks off the top of the CN Tower in Toronto, which has height h and falls freely. His initial velocity is zero. The Rocketeer arrives at the scene a time of t later and dives off the top of the tower to save the student. The Rocketeer leaves the...

I am so sorry if I seem like I don't really care, but I do I am just very confused and really tired plus these things don't come naturally to me :[ that is why I am seeking help, so I really appreciate you helping me! Now with what you have helped me with me I have discovered these equations...

Hi, thanks for responding so you say I need two equations for each phase so i assume my diagram is correct, could you give me an idea which equations I could possibly use and equate to each other to solve for T?

Oh, i got the whole concept wrong, so how would I set up this equation I did something like this, would this be somewhat appropriate,

Homework Statement Problem : During your summer internship for an aerospace company, you are asked to design a small research rocket. The rocket is to be launched from rest from the earth’'s surface and is to reach a maximum height of 990 m above the earth'’s surface. The rocket’'s engines give...

I see, so i use another equation, vf = vi + a*t, then i could plug in the value of Vi i found into the equation and I can solve for t in this new equation that would give me t= sqrt(2gy)/g would that be correct? then I could put this in a simple Vx=d/t constant acceleration equation which would...

Oh I see what you're trying to say I use the kinematic formula of Vf^2=Vi^2+2ad and i solved for Vi, which gave me Vi = sqrt(19.6Y) does that look right? how should I proceed with the horizontal component without keeping time in?

So this is how i re-approached this, 1) i started with the vertical component and used the equation d(y)=Vi*t+(1/2)a*t^2, solved for Vi it became Vi= (d-(1/2)a*t^2)/t 2) i used another equation d= ((vi+vf)/2)t, solved for t = (2d)/vi and vf = 0 at apex of the parabola 3) put equation 2 into...

Hi there, so when I'm thinking about the problem I can say Vxf = Vxi because horizontal is constant, then for the Y velocity it is : Vyf = Vyi + at, which becomes Vyi = gT/2 because final velocity is 0 at the top and time is also half. Since the question was asking for magnitude of the pebble...

sorry, I'm not understanding this concept you say use this equation "d = v1 * t + 0.5 * a * t^2" but within that equation I have 3 unknowns, the displacement(which can be said to be Y, but that is an unknown distance introduced in the question), initial velocity and also time, even if I attempt...

hi, but since the height of the window was never given how do i go on about figuring it out?

Homework Statement The question states : Romeo tosses a pebble at Juliet's window to wake her. Unfortunately, he throws too large a pebble too fast. Just before crashing through the glass, the pebble is moving horizontally, having traveled a horizontal distance x and a vertical distance y as a...