Recent content by haydez98

Confusion with Fourier Transform and Step Function...clarification needed please :) I am required to find the Fourier Transform of (without integration): s(t) = 1 for 0 < t < 4; -t/2 for 4 < t < 6. I understand that for: s(t) = t for 0 < t < 1; 1 for t > 1 that this is the same as...

ah coolness. i didn't know about having to put c_-n in it too thanks so much

okay i'll show you my working out... c_{n}=\frac{1}{T}\int_{0}^{T}s(t)e^{\frac{-j2\pi nt}{T}}dt =\frac{1}{T}\left [\int_{-T/3}^{0}-1e^{\frac{-j2\pi nt}{T}}dt + \int_{0}^{T/3}1e^{\frac{-j2\pi nt}{T}}dt \right ] =\frac{1}{T} \left[\left[\frac{T}{j2\pi n}e^{\frac{-j2\pi nt}{T}}...

fourier series - trig and complex not matching? i am given a signal which can be written as: s(t) = -1 {-1 < t < 0}, 1 {0 < t < 1}, 0 {1 < t < 2} [it's a pulse train] the period, T, is 3. i have calculated the trig. Fourier series representation, which in MATLAB turns out to be correct...

bump... i am having a similar problem... i am given a signal which can be written as: s(t) = -1 {-1 < t < 0}, 1 {0 < t < 1}, 0 {1 < t < 2} [it's a pulse train] the period, T, is 3. i have calculated the trig. Fourier series representation, which in MATLAB turns out to be correct, yet...

ok thanks ^_^

ah cool, thank you very much, that explains lots what I meant by A/3 was that: because sum of moments at A = 0, and L =3 Dy x 3 = (192.6 x 1) + (135.8 x 2) therefore: Dy = [(192.6 x 1) + (135.8 x 2)] /3With the vertical reaction at A has different for Part 2, do I sum the y-components to...

Would the sum of the moments about A just be: (192.6 x 1) + (135.8 x 2) ? And so the reaction at D is the sum of the moments at A/3?

Homework Statement The symmetrical scissors truss is supported at point A and D. The support at D is a rocker bearing and does not produce a horizontal reaction. A, B, C, D, E, & F are pin joints. The members of the truss are not joined to each other where they cross. At A, the angle...