Recent content by Helpme7534

so T=(55)(1.50)+(55)(9.81)

So T=622.05 i didnt get that from no where i went T=ma+Fg

so (1.50)(55)-(9.81)(55)=-524.835N

dude i did what u told me to do i wasnt randomly posting that but if u can't see that.. F=ma F=her mass (aka 55kg, since you may not wan to scroll to the top)(9.81m/s2) F=539.55 N (yes I am grouchy but its only cus I've only been through this with other ppl who after a waste of my time...

lets clarify i only have physics 20-1, and i really need help with this questions, can someone please show me the formulas to use and how to fill them in? it would be greatly appreciated

F=539.55N is that the ans?

so 281.2 is the total force but where do i go from there?

wow so confused so my final answer for the first part will be zero? and for the seconds part it will be zero??

the force of her and the force of gravity?

0, so 85 N is the force of friction?

can you show me how to do a question like this? (keep in mind i only have physics 20-1)

well could the answer be a negative number then? I need a 3 digit answer the second part of the question is The coefficient of friction here is a.bc x 10 ^-d The values of a, b, c, and d respectivly are ____

Homework Statement While running an obstacle course, Jane comes to a rope hanging from a platform. She grabs a rope, which then accelerates her up into the air. Her mass is 55 kg and she accelerates upward at 1.50 m/s2. The tension on the rope is ____N. Homework Equations F=ma The...

85n?

k i appreciate the help but i need to no how to do it, f=ma yes i no that, but i don't no how to get force of friction