Recent content by HJ^2

Oh thanks! And thank you so much for your help + everyone else in this thread :)

Absolutely. I'll have to bring it up to her as I'm sure my class mates had similar concerns.

Fgrav = -9.8*74.4? If that's right, then; Fn = (74.4*6.8411) - (-729.12) = 1238.10

Fn = (m*a) - Fg With variables is; Fn = (74.4 * 6.8411) - 9.8 = 499.177 ?

So fnet would equal Fg + Fn = m*a

okay; sum of forces, as in, Fnet = m*a of which Fnet covers x / y values like friction, gravity, normal force? Am I missing something?

Forgot I had already incorporated 9.8 (gravity) already, my mistake. Since acceleration is the result of NF; would it not be mass * acc (f=ma)

Well the acceleration of the athlete is 6.8411 and there's a -9.8 force as well; -2.9589?

Well the forces acting on the athlete would include gravity & normal force,? Net acc. would have to be zero?

I think so? Since the numbers here can't really be applied to a real life problem and that some values are hardly considered in the equation. The professor of my class is more concerned about if we know how to calculate the material, I think.

I understood the concepts; it was just a weird problem that didn't make a lot of sense at first

I got it! I forgot to square root the final velocity. Vf = 6.1980 a= 6.1980 / 0.906 = 6.8411 6.8411 * 74.4 = 508.908 508.908 /2 = 254.4

Oh whoops, a = (v - v0)/t a = (38.416 - 0)/0.906 = 42.201 f=ma ---> f=74.4*42.201 so f=3139n / 2 (split evenly between two feet) = 1569n?

f=ma as in; f=74.4 * 38.416 Also 254.2 is the answer to the problem as generated via the program I am working this equation through - could this just be incorrect?

f=ma gives me 2858n when the answer should be 254.2?