Recent content by Hn.
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H
[Kinematics] Question involving quadratic equation.
Answer: (7 + 4.28)/2 = 8.68 s or (7 - 4.28)/2 = 2.09 s Since you stated the initial velocity was 4.28, I'm guessing that: t = (7 \pm 4.28)/2 = (v1 \pm v2)/2 So it is equal to say that: t = 1/2(v1\pmv2) = 1/2(7\pm4.28) The initial velocity is found along the...- Hn.
- Post #6
- Forum: Introductory Physics Homework Help
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H
[Kinematics] Question involving quadratic equation.
LowlyPion, you are correct that 7 m/s is a final velocity. However, the equation I used did not require me to find out the Initial Velocity to find the time. BAnders1, thanks for the information.- Hn.
- Post #4
- Forum: Introductory Physics Homework Help
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H
[Kinematics] Question involving quadratic equation.
An object accelerates at the rate of 1.30 m/s^2 over a displacement of 11.8m, reaching a final velocity of 7.00 m/s. For what length of time was it accelerating? Explain the answers. NOTE: Actually, when I first was about to post this, I finally had gotten the answer I needed. However, I cannot...- Hn.
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- Kinematics Quadratic Quadratic equation
- Replies: 6
- Forum: Introductory Physics Homework Help