Recent content by Hoodoo

Answer from the text agrees with what I got. You are picturing them heading in the wrong directions. They are both heading towards each other. Andy is headed south-east (-y) and Sam is headed north-east (+y). The -2.5 degrees tells me that it's below the horizontal which is what my text...

Alright, so I got: -0.3452/7.77 = vfsinσ/vfcosσ -0.0444 = tanσ -2.5 degrees for σ Does that imply it's below the horizontal? Also, followed the instructions on adding the equations together and then squaring. It wasn't until I got to the end that I remembered that sin squared + cos...

Andy is headed south-east and Sam is heading north-east.

Homework Statement Andy (mass 92 kg) and Sam (mass 75 kg) are both on toboggans (each toboggan has a mass of 4.6 kg) traveling on a crash course towards each other. Just as they hit, they lock hands so they move together as one. What is their new speed? In what direction do they travel? mA =...

That is a big mistake.. yes I see what you're saying. Completely removing v1' was totally incorrect but I lucked into the answer in the end. So I should originally isolate the variable that is both unknown and unwanted in the final solution? Then substitute that into the other equation and...

No typo. I get the answer that is given in the text doing what I did. I'm looking for m2. If you get it the other way around, you've already solved the question, haven't you? 0+m2v = m + m2(-v/5) m = m2v + m2v/5 m = 6m2v/5 I removed v1' entirely instead of eliminating it because I...

I got: m = (6m2v)/5) Now I'm supposed to substitute into the equation for conservation of energy.. I end up at the end with: 0 = v((6m2)/5) - ((24m2v)/25)) Therefore, v = 0 or v = 5/4 Sub back into original equation: m = (6m2v)/5 m = (6m25)/5*4 m2 = 2m/3 Now, my main...

Homework Statement Two nuclei make a head-on elastic collision. One nucleus (mass m) is initially stationary. The other nucleus has an initial velocity (v) and a final velocity of (-v/5). What is the mass of this nucleus? Homework Equations conservation of momentum...