Recent content by humanaction

  1. H

    Understanding the Ellipsis in Algebraic Operations

    thank you for your information. my uni allows me to test out of and earn credit for up to calculus iii. i will look into those books. in the meantime, could you try to explain this ellipsis to me? i haven't run into any problems with the other questions from this chapter, I've just never done an...
  2. H

    Understanding the Ellipsis in Algebraic Operations

    i agree. i was going to ask what is the best precalculus book? i am planning on going to uni next autumn and i would like to be able to test out of all my maths if possible to save money. so time is limited. but at the same time i want to learn it right. i enjoy maths and am not just trying to...
  3. H

    Understanding the Ellipsis in Algebraic Operations

    ah yes. so multiplication works the same it seems, but how do you subtract ellipses? sorry I've been out of school for 5 years and never went to uni :(
  4. H

    Understanding the Ellipsis in Algebraic Operations

    How does it not apply? x(xyn-2)-y(xn-2y)= aforementioned dilemma, ignoring the rest of the equation because I'm on my phone...
  5. H

    Understanding the Ellipsis in Algebraic Operations

    Homework Statement Prove xn-yn=(x-y)(xn-1+xn-2y+…+xyn-2+yn-1 Homework Equations 12 basic properties of numbers The Attempt at a Solution I'm all good except I don't see why x2yn-2-xn-2y2=0
  6. H

    Undergrad Formal logic question from beginner

    For the most part. I have zero formal logic and little mathematical background, so it's taking awhile for this to sink in. My philosophy class is telling me that such formalistic logic has no bearing on reality. He says it's because this logic deals not with the content of the strings, or how...
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    Undergrad Formal logic question from beginner

    Hello, I am a complete novice at formal logic and so far removed from mathematical study that I have no idea how the following should be interpreted, or read, and what its implications are: (a∨~a)∨~a⇒a∨(~a∨~a)⇒(a∨~a)⇒((a∧⊤)∨~a)⇒((a∧(b∨~b)∨~a)⇒(((a∧b)∨(a∧~b))∨~a)⇒...