Recent content by humfri

LOL, apparently they operators commute anyway (something I found ages ago but thought I'd done something silly and so ignored my result), thus no uncertainty relation. Nevermind. Thanks for the help anyway, now I actually understand what I need to do next time!

thanks for your reply! do you mean like operator A = [<A1|A|> <A1|A|A2>; <A2|A|A1> <A2|A|A2>] and [<A1|B|> <A1|B|A2>; <A2|B|A1> <A2|B|A2>]cos if I do that I get A = [a1 0; 0 a2] and B= 1/25[9b1+16b2 12b1-12b2; 12b1-12b2 9b1 + 16b2] but then I did do A on A and also A...

:( i think ill go eat some worms... :(

Homework Statement Hi guys! Many time reader, first time poster... I've struggled big time with the following. Any advice at all would be great. I'm so muddled, it's just not funny any more... (plus I'm not really familiar with who to write the mathematic script so please be patient) I...