if the box is moving at constant speed in the x direction then the force MUST be equal to the kinetic friction, correct?
Should I go back, make my sum of Forces in the y = 0 and recalculate the normal force by factoring in the y component of the force, instead of assuming the normal force is...
Homework Statement
The coefficient of kinetic friction between a 20kg box and the floor is 0.40 -> How much work does a pulling force applied 37 degrees above the horizontal do on the box in pulling it 8.0m across the floor at constant speed
Homework Equations
F(kinetic)= F(normal) x...