Selecting and buying mean the same. I used them interchangeably. Do you familiar with the social golfer problem? It is a very famous combinatorial optimization problem. Maybe I could not express as clearly as possible. But actually what I am asking is very similar to that of the social golfer...
So let us say that we have the following chocolate brands
A B C D E
The number of three groups that can be formed with these brands will be 10. The order of your selection does not important and all three chocolate brands in each group should be different as the following
ABC
ABD
ABE
ACD...
There are 10 different chocolates and you want to buy three of them. However, you cannot pick a pair of chocolate more than once. How many different choice you can make??