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Square root involving complex number
No, the problem definitely says C=\frac{1}{\sqrt{ix}} and that there are two roots. Maybe a typo in the book then, I don't know, but if that is the case I have wasted a lot of time... I know, the \frac{1}{2} is from cos^2(\frac{\pi}{4}) from multiplying with the complex conjugate. In...- hypothesis
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- Forum: Calculus and Beyond Homework Help
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Square root involving complex number
I've struggled for days reading about square roots of complex numbers and I get most of the problems but not this one. I really want to understand what is going on in this problem, hope someone can help! 1. The complex number (C) is C = 1/\sqrt{i*x} . find the two roots of C. The solution...- hypothesis
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- Complex Complex number Root Square Square root
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- Forum: Calculus and Beyond Homework Help