Recent content by i5hands

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    Finding removable discontinuity

    Yes, you can factor so there is a value for a when x = 5 you get 3/10. But there is not a value for when x=-5 because after plugging in -5 you get undefined therefore there are no values for B. Thank you so much!
  2. I

    Finding removable discontinuity

    i made a mistake when writing the question, it is f(x) ={ x^2-7x+10 / x^2 - 25
  3. I

    Finding removable discontinuity

    Thank you! There is a Vertical asymptote at x=-5 so does that mean there are no values to make it continuos?
  4. I

    Finding removable discontinuity

    Homework Statement Let f(x)= {x^2-7x+10, for x^2 ≠ 25 { A, for x = 5 { B, for x = -5 Is there a value of A that makes f continuous at x= 5? Is there a value of B that makes f continuous at x= -5?