Recent content by Iconic

Homework Statement A hiker plans to swing on a rope across a ravine in the mountains, as illustrated in the figure, where L = 4.0 m and x = 1.8 m, and to drop when she is just above the far edge. At what minimum horizontal speed should she be moving when she starts to swing(in m/s)? Homework...

Problem: A father pushes horizontally on his daughter's sled to move it up a snowy incline, as illustrated in the figure, with h = 3.6m and θ = 15°. The total mass of the sled and the girl is 35 kg and the coefficient of kinetic friction between the sled runners and the snow is 0.20. If the...

Oops, I forgot to add the subscript i and f on that last equation but what you said was exactly what I meant. Again thanks, I think the only real issue I had with this problem was figuring out how we went from 1/2mvi2-2(u)mgd=1/2mvf2 to vi2- 2(u)gd= vf2 But I understand now that you're...

Ahh, thank you for clearing that up I was having difficulty with defining some forces but that explains it. So it's not the friction force we were trying to get but the magnitude of that frictional force over 1.0m. Thank you so much that really helped!:approve: v2- 2(u)gd= v2

So what I really do is... 1/2mv2-Coefficient(Normal Force)(Distance)= 1/2mv2 Multiply the two from all the variables on the opposing side? Not just 1 mv2- 2Coefficient(Normal Force)(Distance)= mv2 Then Mass is divided canceling out every where v2- 2Coefficient(Normal...

Sorry, for replying so late I'm just taking my time with these posts to ensure I didn't mess up anywhere. Just read your post gneill, THANK YOU very much for that broad and well written explanation. Couple things I need to say though, there might have been a typo, however; after double checking...

I see what you are saying however, after realizing my mistake I now tried to solve the equation with this in mind and still ended up with an incorrect result. 1/2(.75kg)(20m/s2)-(.17f)(.75kg)(9.8m/s2)(1.0m) = 1/2(.75kg)(v2) Simplified. 150-1.2495 = .375(v2) Simplified Again. 148.7505 =...

Homework Statement A 0.75-kg block slides on a frictionless surface with a speed of 20 m/s. It then slides over a rough area 1.0m in length and onto another frictionless surface. The coefficient of kinetic friction between the block and the rough surface is 0.17.What is the speed of the...