hmm i tried using the equation f = m(dv/dt) + v (dm/dt) and p = mv and i can't get the answer. Anw this isn't coursework/schoolwork it is a question i stumbled upon on a old textbook of mine.
The weight of a rocket is 80kN at the instant it takes off , and the products of the combusion are ejected at a velocity of 0.60 kms-1 relative to the rocket. Calculate the rate at which the rocket must be consuming fuel in order to take off vertically. Ans: 134kgs-1
Cant find a solution...