Recent content by idor

Hi, Thank you very much! your confirmation really helps. It just seemed odd to me at first that the capacitor would 'pull in' the dielectric material even when the power source remains connected, after looking at a similar example where it was disconnected first, and the total amount of work...

1. new capacity: ##C = K\cdot C_{0}##. 2. initial potential energy: ##U_{i} = \frac 1 2 \cdot C_{0}V_{0}^2##. 3. final potential energy: ##U_{f} = \frac 1 2 \cdot KC_{0}V_{0}^2##. 4. total work done: ##W_{tot} =\Delta U = U_{f} - U_{i} = \frac 1 2 \cdot (K-1)C_{0}V_{0}^2 > 0##. 5. also total...