if a1 = a2 = a3, and we assume that their directions are:
a1 : of 500 g downwards
a2: of 100 g upwards along the incline
a3: of 50 g upwards
then the equations become (assuming that the tension is T along the length of the string)
(1/2)g - T = (1/2)a
T - (1/10)g sin(30) = (1/10)a
T -...
Okay. I got that question now, but this one is really troubling me. This is what I've tried sofar:
First I draw FBD for each of the blocks. Applying F = MA for each block:
500 g block
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500 g = 1/2 kg
The string attached to it has a tension T.
let it have an acceleration...
Tried the problem but answer is not matching with the given answer. Can you tell me what is the correct answer and how you got it? (problem is attached as image)