Recent content by Immy2000

I know its quite silly however the answer was calculated with that number. Therefore I assume that it was typoed and then answered, then printed and handed out to the students.

Yeah I later realized it was in seconds but as far as the answer goes, its 17.2 hours. Thanks for the help guys! :)

Yeah it is but I am assuming I am supposed to use what the question gives me.. let me redo the calculation with 1738km's though... Alright so I get to the part where you have to square root T^2 and I get 0.21649... days (I think) and if I multiply that by 24, I should get hours, but when I do...

Homework Statement On each of the apollo missions the command module was placed in a very low aprox circular orbit above the moon. Assum the avrg hieght was 60km above surface of moon and moons radius is 7738km. (Mass of moon=7.34x10^22kg) What was the command modules orbital period...

OH MY GOSH I LOVE YOU THANK YOU SO MUCH! Heh. No really, thanks, that really helped. Its so simple...I guess I just need to break it down and go from there. For now.

When I did the calculation I got 6.9 m/s which is not the answer to average velocity, but rather average speed.

Alright, I understand speed now, but if I read correctly, you firstly address velocity. Isn't velocity "change in displacement", not "change in distance" over "change in time"?

~~~~~~~~~~~~~~~~~~~~~~~~~~~~Solved~~~~~~~~~~~~~ Homework Statement A student travels at a constant velocity of 8.0 m/s north for 25 minutes, and then 5.0 m/s south for 15 minutes. Calculate the students... (Answer in brackets) a) Average Velocity (Answer 3.1 m/s North) b) Average Speed...