Okay this is what I updated.
I split the momentum into x and y components.
i did 4.2-3.5=3.4cos35 + v2fcosx
0=3.4sin35 + v2f sinx
i did v2fsinx/v2fcosx and got tanx = 2.09/1.95 so i did the inverse of tan, got that the angle was about 46.98 degrees.
then to calculate for v2f i just plugged in...
Okay, thank you so much for telling me!
I just tried to write LaTeX, I clicked preview and nothing happened to the text so I don't believe I'm writing it correct.
here is my work though:
pi=pf
mv1(initial) + mv2(initial) = mv1 (final) + mv2 (final)
so substitute the values im given...