Recent content by inflames829

thanks for that I have the answer now

does that mean 1 = -1/sinh^2(y) * (coth(y))

sorry but I'm still not getting it, can you give me another hint or show me please

Homework Statement y=arccoth(x), find the derivative Homework Equations cothx - coshx/sinhx The Attempt at a Solution y = arccoth(x) x = coth(y) = cosh(y)/sinh(y) quotient rule = (sinh(y)*sinh(y))-(cosh(y)*cosh(y))/(sinh(y))^2 = sinh^2(y) - cosh^2(y)/sinh^2(y) x=...

ive tried so many differnet ways for this and i still can't get it can someone please help

let F(x) be the antiderivative of the function f(x) = -x sin (pi*x)-3cos(pi*x) such that F(0) = 0.Find F(1/2)

Homework Statement monochromatic light of wavelength 616nm is incident on a narrow slit. On a screen 1.7m away, the distance between the second diffraction minimum and the central maximum is 1.8cm. What is the width of the slit in mm? Homework Equations The Attempt at a Solution...

Homework Statement A thin flake of mica (n= 1.58) is used to cover one slit of a double slit interference arrangement. The central point on the viewing screen is now covered by what had been the 9th bright fringe before the mica was used. What is the thickness of mica if light of wavelength...

thanks. I got the right answer...in the end. I was using a converter for the mach to meters a second conversation that's why i got it wrong. But thanks for the help

ohh, i didnt pick up on the rearranging error. Now I get the horizontal distance to be 5619.51223. Is that right. Then if i divide that by 442.5696 (which is mach 1.5) i get 12.70, but the correct answer is 11, am i still doing something wrong? do i use taht equation?

i still get the same horizontal distance. I use tan theta = opposite/adjacent, which i rearrange to tan theta x adjacent = opposite, so tan 0.73 x 5029 = 4500.54. Is that right because i still get the wrong answer

thanks for the help. I got the right answer

i converted mach to meters a second but if i use 1/1.5 i get 0.73 degrees for theta. Using this i got 3171.18m for the horizontal distance. Now do i use time = distance/velocity, and if so do i keep the speed in mach or meters a second

i did that an got the angle as 0.8867. then i used tan-1 x adjacent equals opposite, which i had as the horizontal distance. Then i used time = distance/velocity but still get the wrong answer. Can you please help, am i still doing something wrong

Homework Statement A jet aircraft traveling with a velocity of mach 1.5 at an altitude of 5029m passes directly over an observer on the ground. How many seconds elapse before the observer experiences the sonic boom created by the jet? speed of sound= 343ms-1 Homework Equations The...