Recent content by inh

ah yea, sorry about that. v = 4.0 fps, the actual acceleration is fps^2, sorry about the confusion

4.0 fps^2 looks like i was off by half :) thanks for the help guys

isnt it 10 * 32.15^2 * 1 and not 10 * 32.15 * 1 ? also, i was simplifying the equation earlier, and i believe i got it down to v^2 = .5gh which netted 4.009 for v for a 1 foot jump. that looks better to me, how about you?

how off am i? using a mass of 10 lbs, height of 1 foot, and g = 32.15 feet, i get 10336.23 for mgh. v^2 = .5 * 10 * 10336.23 v = 227.33 feet per second so to move a 10 weight 1 foot in the air it needs to have a velocity of 227 feet per second? seems a bit high...

exactly what i was looking for thank you very much :)

I don't have a set height, or weight really, just wondering how to determine how much force it takes to make X amont of weight move Y feet vertically. I get the rest of the equation, but what does mgh stand for?

How fast does something need to accelerate in order to jump? Say a weight of 100 lbs, or kg's, etc.