Recent content by invictor

Sorry I will correct this into new post By substiution: 1. u = x^{2}-5 2. du = 2x dx 3. \frac{du}{2x}= dx 4. \int u^{2}x \frac{du}{2x} 5. \int u^{2} \frac{1}{2} du 6. \frac{1}{3} u^{3} \frac{1}{2} + C 7. \frac{1}{6} u^{3} +C 8. \frac{1}{6} (x^{2}-5)^{3} +C 9. \frac{1}{6} [x^{6} -...

So why does both methods differs -125/6 ?

Aha yes my fault but this doesn't explain why i get 125 value from the first method since unfactorise (x^{2} - 5)^{3} = x^{6} - 15x^{4} + 75x^{2} - 125

\int(x^{2}-5)^{2}x dx By substiution: 1. u = x^{2}-5 2. du = 2x dx 3. \frac{du}{2x}= dx 4. \int u^{2}x \frac{du}{2x} 5. \int u^{2} \frac{1}{2} du 6. \frac{1}{3} u^{3} \frac{1}{2} 7. \frac{1}{6} u^{3} 8. \frac{1}{6} (x^{2}-5)^{3} 9. \frac{1}{6} [x^{6} - 15x^{4} + 75x^{2} +125]By...

Thanks i got it now :)

Hello, I am new. I been looking on the net for a guide how to solve the CDF by hand, i know the answer and I am about to crack this baby but I got stuck... Im trying to calculate Cumulative distribution function by hand: \int^{1}_{-1}\frac{1}{2\pi} e^{\frac{-z^{2}}{2}} dz or wolfram alpha...