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    How to Integrate 2/e3x(6+e-3x)dx Using Substitution

    Can't integrate the "e"s here Homework Statement \int 2/e3x(6+e-3x)dx Homework Equations I have no idea as to what equations to use, other than \int eu du = e u + C The Attempt at a Solution \int 2/(6e[SUP]3x[SUP] +1) dx u = 6e[SUP]3x[SUP] +1 du = 18e[SUP]3x[SUP] dx and...
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