sorry about the mistake i made with the problem. yes the problem is (3x-1)/(x(x^2 +4)). From the equation i came up with A/x + Bx + C/ x^2 +4. After multiplying through the equation by the denominator (x(x^2+4)) i get A(x^2 +4) + (Bx +C)(x). That gives me Ax^2 + 4A + Bx^2 + Cx. After equating...
Partial fraction decomposition for...
[b]1. 3x-1 / x(x^2 +4)
Homework Equations
[b]3. A/x + Bx + C/ x^2 +4
after multiplying through by the denominator and my attempt at finding A,B,C i get this:
3x-1/x(x^2+4) = - one fourth / x + one fourth + 3/ x^2 +4. I don't feel...